Messages

1

General discussions (Q&As) / Re: BI and BII conformations

« on: April 12, 2013, 12:27:22 pm »

ps it's BII conformation because is in the range 20, 200 

2

General discussions (Q&As) / Re: BI and BII conformations

« on: April 12, 2013, 12:24:20 pm »

epsilon= -100 zeta= 146.3 epsilon = -100+360= 260 epsilon-zeta=260-146.3 = 113.7

Now I understood.

Thanks!

3

General discussions (Q&As) / Re: BI and BII conformations

« on: April 12, 2013, 11:21:35 am »

I'm sorry Xiang, but I really didn't understand your reply...
if epsilon = 0 to +360 and zeta= 0 to +360 e-z = -360     0        +360, but how can get negative values in this way?

thanks

Caterina Bianchi

4

General discussions (Q&As) / Re: BI and BII conformations

« on: April 11, 2013, 05:18:06 am »

Dear Xiang,

Thanks for your reply! I have another question, because I don't understand what mean  when you say "If the difference (d=e-z) is < 0, then d=d+360",but in this way the values that I will get will be always positive. How you can get -160 degrees?

Regards,

Caterina Bianchi

5

General discussions (Q&As) / BI and BII conformations

« on: April 10, 2013, 12:04:05 pm »

Dear Xiang,

I was reading on the 3DNA hompage that we defined the ranges for BI and BII conformations, but I don't understand what is the range for e-z. Is it -180 to +180 or -360 to +360?

Thanks in advance.

Best regards,

Caterina Bianchi